History of Hindu Mathematics: A Source Book v2.c17.s8.20
History of Hindu Mathematics: A Source Book v2.c17.s8.20
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v2.c17.s8.20
That is to say, $n = ½ (√(8bs + (2a - b)²) - 2a)/b + 1 .$
History of Hindu Mathematics: A Source Book v2.c17.s8.20
That is to say, $n = ½ (√(8bs + (2a - b)²) - 2a)/b + 1 .$