History of Hindu Mathematics: A Source Book v2.c17.s8.49
History of Hindu Mathematics: A Source Book v2.c17.s8.49
- Language
- English
v2.c17.s8.49
That is, to solve ax² + bx = c, we have 4a²x² + 4abx = 4ac, or (2ax + b)² = 4ac + b². Therefore 2ax + b = √(4ac + b²). Hence x = (√(4ac + b²) - b)/2a.