History of Hindu Mathematics: A Source Book v2.c17.s9.16

v2.c17.s9.16

a_1√(b_1 x) & + a_2√(b_2(x - a_1√(b_1 x))) / & + a_3√(b_3{(x - a_1√(b_1 x)) - a_2√(b_2(x - a_1√(b_1 x)))}) / & + \dots + R = x; or (x - a_1 & √(b_1 x)) - a_2√(b_2(x - a_1√(b_1 x))) / & - a_3√(b_3{(x - a_1√(b_1 x)) - a_2√(b_2(x - a_1√(b_1 x)))}) / & - \dots = R.