Indian Mathematics c5.20
Indian Mathematics c5.20
- Language
- English
c5.20
(α) d = a + ⅓ (a√2-a) (β) a = d - 2/15 d (γ) a = d (1 - ⅛ + 1/8.29 - 1/8.29.6 + 1/8.29.6.8)
Indian Mathematics c5.20
(α) d = a + ⅓ (a√2-a) (β) a = d - 2/15 d (γ) a = d (1 - ⅛ + 1/8.29 - 1/8.29.6 + 1/8.29.6.8)