Geometry in Ancient and Medieval India c8.27

c8.27

Now the side of the regular inscribed polygon of 12 sides will be given by S₁₂² - h₆² + ¼ S₆² (where S₆, S₁₂ are the sides of the hexagon and the 12-sided figure respectively.) = (d/12)² + ¼(d/2)² = (d²)/144 + (d²)/16 = (10d²)/144 Hence its perimeter = 12√((10d²)/144) or (perimeter)² = 10d²