A History of the Kerala School of Hindu Astronomy (in Perspective) c8.s6.6

c8.s6.6

'Obtain first the result of multiplying the *jyā* (of a given *dhanus*) by the *trijyā* and dividing the product by the *koṭi* (of the *dhanus*). Multiply this result by the square of the *jya* and divide the square by the *koti*. Thus we obtain a second result, (as also) a sequence of the further results by repeatedly multiplying by the square of the *jya* and dividing by the square of the *koti*. Divide the terms of the sequence in order by the odd numbers 1, 3, 5, etc.; after this, add all the odd terms and subtract from them all the even terms (without disturbing the order of the terms). Thus is obtained the *dhanus* whose two elements are the given *jya* and *koti*. Here, the smaller of the two elements should be taken as the *jya*, since, otherwise, the series obtained will be non-finite (in value).’