The Shulbasutras of Baudhayana, Apastamba, Katyayana and Manava: With Text, English Translation and Commentary c8.t1.60
The Śulbasūtras of Baudhāyana, Āpastamba, Kātyāyana and Mānava: With Text, English Translation and Commentary c8.t1.60
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c8.t1.60
Again *sq* ABCD = EH² + 4 tr. AEH ∴ AH² + AE² = EH² (viii) Dattaa has given another proof of this theorem. Four rectangles each equal to a given rectangle having breadth a, length b and the diagonal c are so constructed that the diagonal of each rectangle forms the side of a square (Fig. 11). Then $c² = (a + b)² - 4 (½ ab)$ or, c² = a² + b².