大方廣佛華嚴經隨疏演義鈔 11.43

11.43

疏「是故一能持多」下，第五別示其相。於中有三：初明以一望多、二例多望一、三結成句數。初中復二：先明一持多依、後例多持一依。今初，又二：先正明依持之義、後「由一有力必不與多」下釋成。亦通妨難。恐有難云：一之與多，俱有有力、無力二義，云何一能攝多？故此通云：由二有力與二無力必不俱故。以能為緣邊，即是有力，要對所起是無力故。思之。

From the Commentary's "Therefore, the one can support the many…" onward, the fifth part distinctively indicates their aspects. Within this there are three: first, clarifying looking from the one toward the many; second, drawing an analogy looking from the many toward the one; third, concluding with the propositional permutations. The first part also has two: first, directly clarifying the one supporting and the many depending; second, drawing the analogy of the many supporting and the one depending. Now for the first, which also has two: first, directly clarifying the meaning of depending and supporting; second, from "Because the one's being efficacious definitely cannot be together with the many…" onward, explaining and completing it. It also resolves an objection. Fearing that someone might object: "Both the one and the many possess the two meanings of being efficacious and being powerless; how can the one encompass the many?" Therefore this resolves it by saying: "Because two efficacies and two powerlessnesses definitely cannot exist together." For the aspect of being able to serve as condition is precisely being efficacious, and it must be powerless with respect to what is brought about. Reflect on this.