一切經音義 22.321
一切經音義 22.321
- Language
- Classical Chinese
22.321
一俱盧舍(依毘曇中一尺五寸為一肘。四肘為一弓。三百弓為一里。四里為一俱盧舍。準計一里三百六十步。則一俱盧舍有一千四百四十步也。依俱舍論第十二云。分析諸色至一極微故一極微為色邊際。七極微為一微量積微至七為一金塵。積七金塵為水塵量水塵積七為一兔毛塵。積七兔毛塵為羊毛塵量積羊毛塵七為一牛毛塵。七牛毛塵為隟遊塵量隟塵七為一蟣量。積七蟣量為一蝨。七蝨為穬麥。七麥為指節。二十四指橫布為肘竪。四肘為弓竪積五百弓為一俱盧舍。即是從肘至阿練若中間道量)。
"One krośa" (According to the Abhidharma, one chi and five cun make one cubit [hasta]. Four cubits make one bow [dhanu]. Three hundred bows make one li. Four li make one krośa. Calculated on the basis of one li being 360 paces, one krośa is 1,440 paces. According to the twelfth fascicle of the Abhidharmakośa-bhāṣya: "When all material form is analysed down to a single paramāṇu, that single paramāṇu is the limit of form. Seven paramāṇus make the measure of one aṇu. Seven aṇus accumulated make one gold-dust particle. Seven gold-dust particles accumulated make the measure of one water-dust particle. Seven water-dust particles accumulated make one hare's-hair particle. Seven hare's-hair particles make the measure of one sheep's-hair particle. Seven sheep's-hair particles accumulated make one ox's-hair particle. Seven ox's-hair particles make the measure of one dust mote floating in a sunbeam. Seven sunbeam motes make the measure of one nit [likṣā]. Seven nits accumulated make one louse [yūka]. Seven lice make one barleycorn [yava]. Seven barleycorns make one finger-joint [aṅguli-parva]. Twenty-four fingers laid side by side make the height of one cubit [hasta]. Four vertical cubits make one bow [dhanu]. Five hundred bows accumulated make one krośa." That is the distance measured from the cubit to an āraṇyaka dwelling).
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- English (machine translation) — English, machine translation
Linked texts (1)
- 阿毘達磨藏顯宗論 — Classical Chinese