History of Hindu Mathematics: A Source Book v2.c17.s17.t5.28

v2.c17.s17.t5.28

If u = m, v = n be a solution of (5.4), another solution will be $u = mq ± pn,$ $v = nq ± α mp;$ where α p² + 1 = q². Therefore, a solution of (5) is $x = y/2a 2(nq ± α mp) - b,$ $z = y(mq ± pn);$ where α p² + 1 = q² and α m² + β = n².