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History of Hindu Mathematics: A Source Book v2.c17.s17.t5.29

History of Hindu Mathematics: A Source Book v2.c17.s17.t5.29

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v2.c17.s17.t5.29

Put n = ar + ½b and y = s/t; then we have $x = s/2at q(2ar + b) ± 2α mp - b,$ $y = s/t,$ $z = s/2t 2mq ± p (2ar + b).$